2(x-5)+3=6x-4(1+x)

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Solution for 2(x-5)+3=6x-4(1+x) equation: 



2(x-5)+3=6x-4(1+x)

We move all terms to the left:

2(x-5)+3-(6x-4(1+x))=0

We add all the numbers together, and all the variables

2(x-5)-(6x-4(x+1))+3=0

We multiply parentheses

2x-(6x-4(x+1))-10+3=0



We calculate terms in parentheses: -(6x-4(x+1)), so:

6x-4(x+1)

We multiply parentheses

6x-4x-4

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

2x-(2x-4)-7=0

We get rid of parentheses

2x-2x+4-7=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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