2(x-5)+3=11(x+2)-29

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Solution for 2(x-5)+3=11(x+2)-29 equation: 



2(x-5)+3=11(x+2)-29

We move all terms to the left:

2(x-5)+3-(11(x+2)-29)=0

We multiply parentheses

2x-(11(x+2)-29)-10+3=0



We calculate terms in parentheses: -(11(x+2)-29), so:

11(x+2)-29

We multiply parentheses

11x+22-29

We add all the numbers together, and all the variables

11x-7

Back to the equation:

-(11x-7)



We add all the numbers together, and all the variables

2x-(11x-7)-7=0

We get rid of parentheses

2x-11x+7-7=0

We add all the numbers together, and all the variables

-9x=0

x=0/-9

x=0

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