2(x-5)+15=3(x-4)+10

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Solution for 2(x-5)+15=3(x-4)+10 equation: 



2(x-5)+15=3(x-4)+10

We move all terms to the left:

2(x-5)+15-(3(x-4)+10)=0

We multiply parentheses

2x-(3(x-4)+10)-10+15=0



We calculate terms in parentheses: -(3(x-4)+10), so:

3(x-4)+10

We multiply parentheses

3x-12+10

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

2x-(3x-2)+5=0

We get rid of parentheses

2x-3x+2+5=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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