2(x-5)(x-5)+1=-7

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Solution for 2(x-5)(x-5)+1=-7 equation: 



2(x-5)(x-5)+1=-7

We move all terms to the left:

2(x-5)(x-5)+1-(-7)=0

We add all the numbers together, and all the variables

2(x-5)(x-5)+8=0

We multiply parentheses ..

2(+x^2-5x-5x+25)+8=0

We multiply parentheses

2x^2-10x-10x+50+8=0

We add all the numbers together, and all the variables

2x^2-20x+58=0

a = 2; b = -20; c = +58;
Δ = b2-4ac
Δ = -202-4·2·58
Δ = -64
Delta is less than zero, so there is no solution for the equation

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