2(x-41)=3(x-3)

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Solution for 2(x-41)=3(x-3) equation: 



2(x-41)=3(x-3)

We move all terms to the left:

2(x-41)-(3(x-3))=0

We multiply parentheses

2x-(3(x-3))-82=0



We calculate terms in parentheses: -(3(x-3)), so:

3(x-3)

We multiply parentheses

3x-9

Back to the equation:

-(3x-9)



We get rid of parentheses

2x-3x+9-82=0

We add all the numbers together, and all the variables

-1x-73=0

We move all terms containing x to the left, all other terms to the right

-x=73

x=73/-1

x=-73

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