2(x-40)=3(100-x)

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Solution for 2(x-40)=3(100-x) equation: 



2(x-40)=3(100-x)

We move all terms to the left:

2(x-40)-(3(100-x))=0

We add all the numbers together, and all the variables

2(x-40)-(3(-1x+100))=0

We multiply parentheses

2x-(3(-1x+100))-80=0



We calculate terms in parentheses: -(3(-1x+100)), so:

3(-1x+100)

We multiply parentheses

-3x+300

Back to the equation:

-(-3x+300)



We get rid of parentheses

2x+3x-300-80=0

We add all the numbers together, and all the variables

5x-380=0

We move all terms containing x to the left, all other terms to the right

5x=380

x=380/5

x=76

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