2(x-4)=4x+3x+12=

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Solution for 2(x-4)=4x+3x+12= equation: 



2(x-4)=4x+3x+12=

We move all terms to the left:

2(x-4)-(4x+3x+12)=0

We add all the numbers together, and all the variables

2(x-4)-(7x+12)=0

We multiply parentheses

2x-(7x+12)-8=0

We get rid of parentheses

2x-7x-12-8=0

We add all the numbers together, and all the variables

-5x-20=0

We move all terms containing x to the left, all other terms to the right

-5x=20

x=20/-5

x=-4

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