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2(x-4)=3(5-x)
We move all terms to the left:
2(x-4)-(3(5-x))=0
We add all the numbers together, and all the variables
2(x-4)-(3(-1x+5))=0
We multiply parentheses
2x-(3(-1x+5))-8=0
We calculate terms in parentheses: -(3(-1x+5)), so:We get rid of parentheses
3(-1x+5)
We multiply parentheses
-3x+15
Back to the equation:
-(-3x+15)
2x+3x-15-8=0
We add all the numbers together, and all the variables
5x-23=0
We move all terms containing x to the left, all other terms to the right
5x=23
x=23/5
x=4+3/5
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