2(x-4)=2+1/2x

Solution for 2(x-4)=2+1/2x equation:

2(x-4)=2+1/2x

We move all terms to the left:

2(x-4)-(2+1/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2(x-4)-(1/2x+2)=0

We multiply parentheses

2x-(1/2x+2)-8=0

We get rid of parentheses

2x-1/2x-2-8=0

We multiply all the terms by the denominator


2x*2x-2*2x-8*2x-1=0

Wy multiply elements

4x^2-4x-16x-1=0

We add all the numbers together, and all the variables

4x^2-20x-1=0

a = 4; b = -20; c = -1;
Δ = b2-4ac
Δ = -202-4·4·(-1)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{26}}{2*4}=\frac{20-4\sqrt{26}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{26}}{2*4}=\frac{20+4\sqrt{26}}{8}
$