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2(x-4)=12+2x=8
We move all terms to the left:
2(x-4)-(12+2x)=0
We add all the numbers together, and all the variables
2(x-4)-(2x+12)=0
We multiply parentheses
2x-(2x+12)-8=0
We get rid of parentheses
2x-2x-12-8=0
We add all the numbers together, and all the variables
-20!=0
There is no solution for this equation
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