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2(x-4)+8x=10x-8
We move all terms to the left:
2(x-4)+8x-(10x-8)=0
We add all the numbers together, and all the variables
8x+2(x-4)-(10x-8)=0
We multiply parentheses
8x+2x-(10x-8)-8=0
We get rid of parentheses
8x+2x-10x+8-8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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