2(x-4)+7=4x-2(1+x)

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Solution for 2(x-4)+7=4x-2(1+x) equation: 



2(x-4)+7=4x-2(1+x)

We move all terms to the left:

2(x-4)+7-(4x-2(1+x))=0

We add all the numbers together, and all the variables

2(x-4)-(4x-2(x+1))+7=0

We multiply parentheses

2x-(4x-2(x+1))-8+7=0



We calculate terms in parentheses: -(4x-2(x+1)), so:

4x-2(x+1)

We multiply parentheses

4x-2x-2

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

2x-(2x-2)-1=0

We get rid of parentheses

2x-2x+2-1=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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