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2(x-4)+5x=-3(x-7)
We move all terms to the left:
2(x-4)+5x-(-3(x-7))=0
We add all the numbers together, and all the variables
5x+2(x-4)-(-3(x-7))=0
We multiply parentheses
5x+2x-(-3(x-7))-8=0
We calculate terms in parentheses: -(-3(x-7)), so:We add all the numbers together, and all the variables
-3(x-7)
We multiply parentheses
-3x+21
Back to the equation:
-(-3x+21)
7x-(-3x+21)-8=0
We get rid of parentheses
7x+3x-21-8=0
We add all the numbers together, and all the variables
10x-29=0
We move all terms containing x to the left, all other terms to the right
10x=29
x=29/10
x=2+9/10
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