2(x-4)+5(x+1)-8(x-4)=0

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Solution for 2(x-4)+5(x+1)-8(x-4)=0 equation:


Simplifying
2(x + -4) + 5(x + 1) + -8(x + -4) = 0

Reorder the terms:
2(-4 + x) + 5(x + 1) + -8(x + -4) = 0
(-4 * 2 + x * 2) + 5(x + 1) + -8(x + -4) = 0
(-8 + 2x) + 5(x + 1) + -8(x + -4) = 0

Reorder the terms:
-8 + 2x + 5(1 + x) + -8(x + -4) = 0
-8 + 2x + (1 * 5 + x * 5) + -8(x + -4) = 0
-8 + 2x + (5 + 5x) + -8(x + -4) = 0

Reorder the terms:
-8 + 2x + 5 + 5x + -8(-4 + x) = 0
-8 + 2x + 5 + 5x + (-4 * -8 + x * -8) = 0
-8 + 2x + 5 + 5x + (32 + -8x) = 0

Reorder the terms:
-8 + 5 + 32 + 2x + 5x + -8x = 0

Combine like terms: -8 + 5 = -3
-3 + 32 + 2x + 5x + -8x = 0

Combine like terms: -3 + 32 = 29
29 + 2x + 5x + -8x = 0

Combine like terms: 2x + 5x = 7x
29 + 7x + -8x = 0

Combine like terms: 7x + -8x = -1x
29 + -1x = 0

Solving
29 + -1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-29' to each side of the equation.
29 + -29 + -1x = 0 + -29

Combine like terms: 29 + -29 = 0
0 + -1x = 0 + -29
-1x = 0 + -29

Combine like terms: 0 + -29 = -29
-1x = -29

Divide each side by '-1'.
x = 29

Simplifying
x = 29

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