2(x-4)+3x=6+5(x-2)-4

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Solution for 2(x-4)+3x=6+5(x-2)-4 equation: 



2(x-4)+3x=6+5(x-2)-4

We move all terms to the left:

2(x-4)+3x-(6+5(x-2)-4)=0

We add all the numbers together, and all the variables

3x+2(x-4)-(6+5(x-2)-4)=0

We multiply parentheses

3x+2x-(6+5(x-2)-4)-8=0



We calculate terms in parentheses: -(6+5(x-2)-4), so:

6+5(x-2)-4

determiningTheFunctionDomain
5(x-2)+6-4

We add all the numbers together, and all the variables

5(x-2)+2

We multiply parentheses

5x-10+2

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We add all the numbers together, and all the variables

5x-(5x-8)-8=0

We get rid of parentheses

5x-5x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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