2(x-4)+3(x+1)=35

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Solution for 2(x-4)+3(x+1)=35 equation: 



2(x-4)+3(x+1)=35

We move all terms to the left:

2(x-4)+3(x+1)-(35)=0

We multiply parentheses

2x+3x-8+3-35=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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