2(x-3)=6(x+2)

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Solution for 2(x-3)=6(x+2) equation: 



2(x-3)=6(x+2)

We move all terms to the left:

2(x-3)-(6(x+2))=0

We multiply parentheses

2x-(6(x+2))-6=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

2x-6x-12-6=0

We add all the numbers together, and all the variables

-4x-18=0

We move all terms containing x to the left, all other terms to the right

-4x=18

x=18/-4

x=-4+1/2

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