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2(x-3)=5x-2(x+2)
We move all terms to the left:
2(x-3)-(5x-2(x+2))=0
We multiply parentheses
2x-(5x-2(x+2))-6=0
We calculate terms in parentheses: -(5x-2(x+2)), so:We get rid of parentheses
5x-2(x+2)
We multiply parentheses
5x-2x-4
We add all the numbers together, and all the variables
3x-4
Back to the equation:
-(3x-4)
2x-3x+4-6=0
We add all the numbers together, and all the variables
-1x-2=0
We move all terms containing x to the left, all other terms to the right
-x=2
x=2/-1
x=-2
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