2(x-3)=2(x+1)-8

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Solution for 2(x-3)=2(x+1)-8 equation: 



2(x-3)=2(x+1)-8

We move all terms to the left:

2(x-3)-(2(x+1)-8)=0

We multiply parentheses

2x-(2(x+1)-8)-6=0



We calculate terms in parentheses: -(2(x+1)-8), so:

2(x+1)-8

We multiply parentheses

2x+2-8

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

2x-2x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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