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2(x-3)=1/5(4x-12)
We move all terms to the left:
2(x-3)-(1/5(4x-12))=0
Domain of the equation: 5(4x-12))!=0We multiply parentheses
x∈R
2x-(1/5(4x-12))-6=0
We multiply all the terms by the denominator
2x*5(4x-12))-(1-6*5(4x-12))=0
Wy multiply elements
10x^2(4-30x(4=0
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