2(x-3)=-2x+4(x-3)+6

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Solution for 2(x-3)=-2x+4(x-3)+6 equation: 



2(x-3)=-2x+4(x-3)+6

We move all terms to the left:

2(x-3)-(-2x+4(x-3)+6)=0

We multiply parentheses

2x-(-2x+4(x-3)+6)-6=0



We calculate terms in parentheses: -(-2x+4(x-3)+6), so:

-2x+4(x-3)+6

We multiply parentheses

-2x+4x-12+6

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

2x-2x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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