2(x-3)=((x+4)/(4))

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Solution for 2(x-3)=((x+4)/(4)) equation: 



2(x-3)=((x+4)/(4))

We move all terms to the left:

2(x-3)-(((x+4)/(4)))=0

We multiply parentheses

2x-(((x+4)/4))-6=0

We multiply all the terms by the denominator


2x*4))-(((x+4)-6*4))=0

We add all the numbers together, and all the variables

2x*4))-(((x+4)=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$

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