2(x-3)-7=7-5(x+1)

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Solution for 2(x-3)-7=7-5(x+1) equation: 



2(x-3)-7=7-5(x+1)

We move all terms to the left:

2(x-3)-7-(7-5(x+1))=0

We multiply parentheses

2x-(7-5(x+1))-6-7=0



We calculate terms in parentheses: -(7-5(x+1)), so:

7-5(x+1)

determiningTheFunctionDomain
-5(x+1)+7

We multiply parentheses

-5x-5+7

We add all the numbers together, and all the variables

-5x+2

Back to the equation:

-(-5x+2)



We add all the numbers together, and all the variables

2x-(-5x+2)-13=0

We get rid of parentheses

2x+5x-2-13=0

We add all the numbers together, and all the variables

7x-15=0

We move all terms containing x to the left, all other terms to the right

7x=15

x=15/7

x=2+1/7

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