2(x-3)-4(x+12)=2(x+27)

Solution for 2(x-3)-4(x+12)=2(x+27) equation:

2(x-3)-4(x+12)=2(x+27)

We move all terms to the left:

2(x-3)-4(x+12)-(2(x+27))=0

We multiply parentheses

2x-4x-(2(x+27))-6-48=0


We calculate terms in parentheses: -(2(x+27)), so:

2(x+27)

We multiply parentheses

2x+54

Back to the equation:

-(2x+54)


We add all the numbers together, and all the variables

-2x-(2x+54)-54=0

We get rid of parentheses

-2x-2x-54-54=0

We add all the numbers together, and all the variables

-4x-108=0

We move all terms containing x to the left, all other terms to the right

-4x=108

x=108/-4

x=-27