2(x-3)-3(x-4)=2.5(x-2)+10

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Solution for 2(x-3)-3(x-4)=2.5(x-2)+10 equation: 



2(x-3)-3(x-4)=2.5(x-2)+10

We move all terms to the left:

2(x-3)-3(x-4)-(2.5(x-2)+10)=0

We multiply parentheses

2x-3x-(2.5(x-2)+10)-6+12=0



We calculate terms in parentheses: -(2.5(x-2)+10), so:

2.5(x-2)+10

We multiply parentheses

2.5x-5+10

We add all the numbers together, and all the variables

2.5x+5

Back to the equation:

-(2.5x+5)



We add all the numbers together, and all the variables

-1x-(2.5x+5)+6=0

We get rid of parentheses

-1x-2.5x-5+6=0

We add all the numbers together, and all the variables

-3.5x+1=0

We move all terms containing x to the left, all other terms to the right

-3.5x=-1

x=-1/-3.5

x=1/3.5

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