2(x-3)-3(x-2)+1=(1-x)/2

Solution for 2(x-3)-3(x-2)+1=(1-x)/2 equation:

2(x-3)-3(x-2)+1=(1-x)/2

We simplify the equation to the form, which is simple to understand 
2(x-3)-3(x-2)+1=(1-x)/2

Reorder the terms in parentheses
+(+2x-6)-3*(x-2)+1=(1-x)/2

Remove unnecessary parentheses
+2x-6-3+*(+x-2+)+1=+(+1-x+)+/2

Reorder the terms in parentheses
+2x-6+(-3x+6)+1=(1-x)/2

Remove unnecessary parentheses
+2x-6-3x+6+1=+(+1-x+)+/2

Reorder the terms in parentheses
+2x-6-3x+6+1=( + 0.5-0.5x)

Remove unnecessary parentheses
+2x-6-3x+6+1=0.5-0.5x

We move all terms containing x to the left and all other terms to the right. 
+2x-3x + 0.5x=0.5+6-6-1

We simplify left and right side of the equation. 
-0.5x=-0.5

We divide both sides of the equation by -0.5 to get x. 
x=1