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2(x-3)+9=2(x+1)+x
We move all terms to the left:
2(x-3)+9-(2(x+1)+x)=0
We multiply parentheses
2x-(2(x+1)+x)-6+9=0
We calculate terms in parentheses: -(2(x+1)+x), so:We add all the numbers together, and all the variables
2(x+1)+x
We add all the numbers together, and all the variables
x+2(x+1)
We multiply parentheses
x+2x+2
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
2x-(3x+2)+3=0
We get rid of parentheses
2x-3x-2+3=0
We add all the numbers together, and all the variables
-1x+1=0
We move all terms containing x to the left, all other terms to the right
-x=-1
x=-1/-1
x=1
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