2(x-3)+7x=1/3(6x-3)

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Solution for 2(x-3)+7x=1/3(6x-3) equation: 



2(x-3)+7x=1/3(6x-3)

We move all terms to the left:

2(x-3)+7x-(1/3(6x-3))=0



Domain of the equation: 3(6x-3))!=0

x∈R



We add all the numbers together, and all the variables

7x+2(x-3)-(1/3(6x-3))=0

We multiply parentheses

7x+2x-(1/3(6x-3))-6=0

We multiply all the terms by the denominator


7x*3(6x-3))+2x*3(6x-3))-(1-6*3(6x-3))=0

We add all the numbers together, and all the variables

7x*3(6x-3))+2x*3(6x-3))-(1-6*3(6x=0

Wy multiply elements

63x^3(6-3))-(1-6*3(6x=0

We do not support expression: x^3(6

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