2(x-3)+3x=3(2x-4)

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Solution for 2(x-3)+3x=3(2x-4) equation: 



2(x-3)+3x=3(2x-4)

We move all terms to the left:

2(x-3)+3x-(3(2x-4))=0

We add all the numbers together, and all the variables

3x+2(x-3)-(3(2x-4))=0

We multiply parentheses

3x+2x-(3(2x-4))-6=0



We calculate terms in parentheses: -(3(2x-4)), so:

3(2x-4)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

5x-(6x-12)-6=0

We get rid of parentheses

5x-6x+12-6=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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