2(x-3)+2=3(x-2)

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Solution for 2(x-3)+2=3(x-2) equation: 



2(x-3)+2=3(x-2)

We move all terms to the left:

2(x-3)+2-(3(x-2))=0

We multiply parentheses

2x-(3(x-2))-6+2=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

2x-(3x-6)-4=0

We get rid of parentheses

2x-3x+6-4=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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