2(x-3)+10(x-4)=-7(x-5)

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Solution for 2(x-3)+10(x-4)=-7(x-5) equation:


2(x-3)+10(x-4)=-7(x-5)

We simplify the equation to the form, which is simple to understand
2(x-3)+10(x-4)=-7(x-5)

Reorder the terms in parentheses
+(+2x-6)+10*(x-4)=-7*(x-5)

Remove unnecessary parentheses
+2x-6+10+*(+x-4+)=-7+*(+x-5+)

Reorder the terms in parentheses
+2x-6+(+10x-40)=-7*(x-5)

Remove unnecessary parentheses
+2x-6+10x-40=-7+*(+x-5+)

Reorder the terms in parentheses
+2x-6+10x-40=+(-7x+35)

Remove unnecessary parentheses
+2x-6+10x-40=-7x+35

We move all terms containing x to the left and all other terms to the right.
+2x+10x+7x=+35+6+40

We simplify left and right side of the equation.
+19x=+81

We divide both sides of the equation by 19 to get x.
x=4.2631578947368

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