2(x-28)-5(x+32)=4-7(x-20)

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Solution for 2(x-28)-5(x+32)=4-7(x-20) equation: 



2(x-28)-5(x+32)=4-7(x-20)

We move all terms to the left:

2(x-28)-5(x+32)-(4-7(x-20))=0

We multiply parentheses

2x-5x-(4-7(x-20))-56-160=0



We calculate terms in parentheses: -(4-7(x-20)), so:

4-7(x-20)

determiningTheFunctionDomain
-7(x-20)+4

We multiply parentheses

-7x+140+4

We add all the numbers together, and all the variables

-7x+144

Back to the equation:

-(-7x+144)



We add all the numbers together, and all the variables

-3x-(-7x+144)-216=0

We get rid of parentheses

-3x+7x-144-216=0

We add all the numbers together, and all the variables

4x-360=0

We move all terms containing x to the left, all other terms to the right

4x=360

x=360/4

x=90

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