2(x-2)=8x+2-4(-2x-1)

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Solution for 2(x-2)=8x+2-4(-2x-1) equation: 



2(x-2)=8x+2-4(-2x-1)

We move all terms to the left:

2(x-2)-(8x+2-4(-2x-1))=0

We multiply parentheses

2x-(8x+2-4(-2x-1))-4=0



We calculate terms in parentheses: -(8x+2-4(-2x-1)), so:

8x+2-4(-2x-1)

determiningTheFunctionDomain
8x-4(-2x-1)+2

We multiply parentheses

8x+8x+4+2

We add all the numbers together, and all the variables

16x+6

Back to the equation:

-(16x+6)



We get rid of parentheses

2x-16x-6-4=0

We add all the numbers together, and all the variables

-14x-10=0

We move all terms containing x to the left, all other terms to the right

-14x=10

x=10/-14

x=-5/7

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