2(x-2)+2x=4(x+4)-20

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Solution for 2(x-2)+2x=4(x+4)-20 equation: 



2(x-2)+2x=4(x+4)-20

We move all terms to the left:

2(x-2)+2x-(4(x+4)-20)=0

We add all the numbers together, and all the variables

2x+2(x-2)-(4(x+4)-20)=0

We multiply parentheses

2x+2x-(4(x+4)-20)-4=0



We calculate terms in parentheses: -(4(x+4)-20), so:

4(x+4)-20

We multiply parentheses

4x+16-20

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

4x-(4x-4)-4=0

We get rid of parentheses

4x-4x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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