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2(x-10)=3(5+x)
We move all terms to the left:
2(x-10)-(3(5+x))=0
We add all the numbers together, and all the variables
2(x-10)-(3(x+5))=0
We multiply parentheses
2x-(3(x+5))-20=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
2x-3x-15-20=0
We add all the numbers together, and all the variables
-1x-35=0
We move all terms containing x to the left, all other terms to the right
-x=35
x=35/-1
x=-35
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