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2(x-1)=5x+2(x-3)+19
We move all terms to the left:
2(x-1)-(5x+2(x-3)+19)=0
We multiply parentheses
2x-(5x+2(x-3)+19)-2=0
We calculate terms in parentheses: -(5x+2(x-3)+19), so:We get rid of parentheses
5x+2(x-3)+19
We multiply parentheses
5x+2x-6+19
We add all the numbers together, and all the variables
7x+13
Back to the equation:
-(7x+13)
2x-7x-13-2=0
We add all the numbers together, and all the variables
-5x-15=0
We move all terms containing x to the left, all other terms to the right
-5x=15
x=15/-5
x=-3
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