2(x-1)/6=2(x+2)/12

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Solution for 2(x-1)/6=2(x+2)/12 equation:



2(x-1)/6=2(x+2)/12
We move all terms to the left:
2(x-1)/6-(2(x+2)/12)=0
We calculate fractions
2x/()+(-(2(x+2)*6)/()=0
We calculate terms in parentheses: +(-(2(x+2)*6)/(), so:
-(2(x+2)*6)/(
We multiply all the terms by the denominator
-(2(x+2)*6)
We calculate terms in parentheses: -(2(x+2)*6), so:
2(x+2)*6
We multiply parentheses
12x+24
Back to the equation:
-(12x+24)
We get rid of parentheses
-12x-24
Back to the equation:
+(-12x-24)
We get rid of parentheses
2x/()-12x-24=0
We multiply all the terms by the denominator
2x-12x*()-24*()=0
We add all the numbers together, and all the variables
2x-12x*()=0

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