2(x-1)-4(x-2)=3(x-3)+5

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Solution for 2(x-1)-4(x-2)=3(x-3)+5 equation: 



2(x-1)-4(x-2)=3(x-3)+5

We move all terms to the left:

2(x-1)-4(x-2)-(3(x-3)+5)=0

We multiply parentheses

2x-4x-(3(x-3)+5)-2+8=0



We calculate terms in parentheses: -(3(x-3)+5), so:

3(x-3)+5

We multiply parentheses

3x-9+5

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

-2x-(3x-4)+6=0

We get rid of parentheses

-2x-3x+4+6=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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