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2(x-1)+3x=4-2(x-3)
We move all terms to the left:
2(x-1)+3x-(4-2(x-3))=0
We add all the numbers together, and all the variables
3x+2(x-1)-(4-2(x-3))=0
We multiply parentheses
3x+2x-(4-2(x-3))-2=0
We calculate terms in parentheses: -(4-2(x-3)), so:We add all the numbers together, and all the variables
4-2(x-3)
determiningTheFunctionDomain -2(x-3)+4
We multiply parentheses
-2x+6+4
We add all the numbers together, and all the variables
-2x+10
Back to the equation:
-(-2x+10)
5x-(-2x+10)-2=0
We get rid of parentheses
5x+2x-10-2=0
We add all the numbers together, and all the variables
7x-12=0
We move all terms containing x to the left, all other terms to the right
7x=12
x=12/7
x=1+5/7
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