2(x-1)+3(1-2x)=4(x+1)+13

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Solution for 2(x-1)+3(1-2x)=4(x+1)+13 equation: 



2(x-1)+3(1-2x)=4(x+1)+13

We move all terms to the left:

2(x-1)+3(1-2x)-(4(x+1)+13)=0

We add all the numbers together, and all the variables

2(x-1)+3(-2x+1)-(4(x+1)+13)=0

We multiply parentheses

2x-6x-(4(x+1)+13)-2+3=0



We calculate terms in parentheses: -(4(x+1)+13), so:

4(x+1)+13

We multiply parentheses

4x+4+13

We add all the numbers together, and all the variables

4x+17

Back to the equation:

-(4x+17)



We add all the numbers together, and all the variables

-4x-(4x+17)+1=0

We get rid of parentheses

-4x-4x-17+1=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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