2(x-1)+2(x+1)=6(x+3)-5(2-7x)

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Solution for 2(x-1)+2(x+1)=6(x+3)-5(2-7x) equation: 



2(x-1)+2(x+1)=6(x+3)-5(2-7x)

We move all terms to the left:

2(x-1)+2(x+1)-(6(x+3)-5(2-7x))=0

We add all the numbers together, and all the variables

2(x-1)+2(x+1)-(6(x+3)-5(-7x+2))=0

We multiply parentheses

2x+2x-(6(x+3)-5(-7x+2))-2+2=0



We calculate terms in parentheses: -(6(x+3)-5(-7x+2)), so:

6(x+3)-5(-7x+2)

We multiply parentheses

6x+35x+18-10

We add all the numbers together, and all the variables

41x+8

Back to the equation:

-(41x+8)



We add all the numbers together, and all the variables

4x-(41x+8)=0

We get rid of parentheses

4x-41x-8=0

We add all the numbers together, and all the variables

-37x-8=0

We move all terms containing x to the left, all other terms to the right

-37x=8

x=8/-37

x=-8/37

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