2(x-1)(x+1)=2

Solution for 2(x-1)(x+1)=2 equation:

Simplifying
2(x + -1)(x + 1) = 2

Reorder the terms:
2(-1 + x)(x + 1) = 2

Reorder the terms:
2(-1 + x)(1 + x) = 2

Multiply (-1 + x) * (1 + x)
2(-1(1 + x) + x(1 + x)) = 2
2((1 * -1 + x * -1) + x(1 + x)) = 2
2((-1 + -1x) + x(1 + x)) = 2
2(-1 + -1x + (1 * x + x * x)) = 2
2(-1 + -1x + (1x + x2)) = 2

Combine like terms: -1x + 1x = 0
2(-1 + 0 + x2) = 2
2(-1 + x2) = 2
(-1 * 2 + x2 * 2) = 2
(-2 + 2x2) = 2

Solving
-2 + 2x2 = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 2x2 = 2 + 2

Combine like terms: -2 + 2 = 0
0 + 2x2 = 2 + 2
2x2 = 2 + 2

Combine like terms: 2 + 2 = 4
2x2 = 4

Divide each side by '2'.
x2 = 2

Simplifying
x2 = 2

Take the square root of each side:
x = {-1.414213562, 1.414213562}