2(x-1)(3x+1)=(3x+2)(2x-1)

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Solution for 2(x-1)(3x+1)=(3x+2)(2x-1) equation: 



2(x-1)(3x+1)=(3x+2)(2x-1)

We move all terms to the left:

2(x-1)(3x+1)-((3x+2)(2x-1))=0

We multiply parentheses ..

2(+3x^2+x-3x-1)-((3x+2)(2x-1))=0



We calculate terms in parentheses: -((3x+2)(2x-1)), so:

(3x+2)(2x-1)

We multiply parentheses ..

(+6x^2-3x+4x-2)

We get rid of parentheses

6x^2-3x+4x-2

We add all the numbers together, and all the variables

6x^2+x-2

Back to the equation:

-(6x^2+x-2)



We multiply parentheses

6x^2+2x-6x-(6x^2+x-2)-2=0

We get rid of parentheses

6x^2-6x^2+2x-6x-x+2-2=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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