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2(x+7)=5/3-3(x-5)
We move all terms to the left:
2(x+7)-(5/3-3(x-5))=0
Domain of the equation: 3-3(x-5))!=0We multiply parentheses
We move all terms containing x to the left, all other terms to the right
-3(x-5))!=-3
x∈R
2x-(5/3-3(x-5))+14=0
We multiply all the terms by the denominator
2x*3-3(x-5))-(5-3(x-5))+14*3=0
Wy multiply elements
6x-3(x-5))-(5-3(x-5))+14*3=0
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