2(x+5)x+x+5=220

Solution for 2(x+5)x+x+5=220 equation:

2(x+5)x+x+5=220

We move all terms to the left:

2(x+5)x+x+5-(220)=0

We add all the numbers together, and all the variables

x+2(x+5)x-215=0

We multiply parentheses

2x^2+x+10x-215=0

We add all the numbers together, and all the variables

2x^2+11x-215=0

a = 2; b = 11; c = -215;
Δ = b2-4ac
Δ = 112-4·2·(-215)
Δ = 1841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1841}}{2*2}=\frac{-11-\sqrt{1841}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1841}}{2*2}=\frac{-11+\sqrt{1841}}{4}
$