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2(x+5)=-2(x-3)+x+1
We move all terms to the left:
2(x+5)-(-2(x-3)+x+1)=0
We multiply parentheses
2x-(-2(x-3)+x+1)+10=0
We calculate terms in parentheses: -(-2(x-3)+x+1), so:We get rid of parentheses
-2(x-3)+x+1
We add all the numbers together, and all the variables
x-2(x-3)+1
We multiply parentheses
x-2x+6+1
We add all the numbers together, and all the variables
-1x+7
Back to the equation:
-(-1x+7)
2x+1x-7+10=0
We add all the numbers together, and all the variables
3x+3=0
We move all terms containing x to the left, all other terms to the right
3x=-3
x=-3/3
x=-1
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