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2(x+5)-7=3(4-x)+1
We move all terms to the left:
2(x+5)-7-(3(4-x)+1)=0
We add all the numbers together, and all the variables
2(x+5)-(3(-1x+4)+1)-7=0
We multiply parentheses
2x-(3(-1x+4)+1)+10-7=0
We calculate terms in parentheses: -(3(-1x+4)+1), so:We add all the numbers together, and all the variables
3(-1x+4)+1
We multiply parentheses
-3x+12+1
We add all the numbers together, and all the variables
-3x+13
Back to the equation:
-(-3x+13)
2x-(-3x+13)+3=0
We get rid of parentheses
2x+3x-13+3=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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