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2(x+5)+4x-9=2x+7-2(3-x)
We move all terms to the left:
2(x+5)+4x-9-(2x+7-2(3-x))=0
We add all the numbers together, and all the variables
2(x+5)+4x-(2x+7-2(-1x+3))-9=0
We add all the numbers together, and all the variables
4x+2(x+5)-(2x+7-2(-1x+3))-9=0
We multiply parentheses
4x+2x-(2x+7-2(-1x+3))+10-9=0
We calculate terms in parentheses: -(2x+7-2(-1x+3)), so:We add all the numbers together, and all the variables
2x+7-2(-1x+3)
determiningTheFunctionDomain 2x-2(-1x+3)+7
We multiply parentheses
2x+2x-6+7
We add all the numbers together, and all the variables
4x+1
Back to the equation:
-(4x+1)
6x-(4x+1)+1=0
We get rid of parentheses
6x-4x-1+1=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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