2(x+5)+3(x+2)=41

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Solution for 2(x+5)+3(x+2)=41 equation: 



2(x+5)+3(x+2)=41

We move all terms to the left:

2(x+5)+3(x+2)-(41)=0

We multiply parentheses

2x+3x+10+6-41=0

We add all the numbers together, and all the variables

5x-25=0

We move all terms containing x to the left, all other terms to the right

5x=25

x=25/5

x=5

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