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2(x+5)+2(2x+2)=4(x+4)+2(x-2)
We move all terms to the left:
2(x+5)+2(2x+2)-(4(x+4)+2(x-2))=0
We multiply parentheses
2x+4x-(4(x+4)+2(x-2))+10+4=0
We calculate terms in parentheses: -(4(x+4)+2(x-2)), so:We add all the numbers together, and all the variables
4(x+4)+2(x-2)
We multiply parentheses
4x+2x+16-4
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
6x-(6x+12)+14=0
We get rid of parentheses
6x-6x-12+14=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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